Integrand size = 19, antiderivative size = 264 \[ \int \frac {(a+b x)^{5/2}}{\sqrt [4]{c+d x}} \, dx=\frac {16 (b c-a d)^2 \sqrt {a+b x} (c+d x)^{3/4}}{39 d^3}-\frac {40 (b c-a d) (a+b x)^{3/2} (c+d x)^{3/4}}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}-\frac {32 (b c-a d)^{15/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} E\left (\left .\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{39 b^{3/4} d^4 \sqrt {a+b x}}+\frac {32 (b c-a d)^{15/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{39 b^{3/4} d^4 \sqrt {a+b x}} \]
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Time = 0.21 (sec) , antiderivative size = 264, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.421, Rules used = {52, 65, 313, 230, 227, 1214, 1213, 435} \[ \int \frac {(a+b x)^{5/2}}{\sqrt [4]{c+d x}} \, dx=\frac {32 (b c-a d)^{15/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{39 b^{3/4} d^4 \sqrt {a+b x}}-\frac {32 (b c-a d)^{15/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} E\left (\left .\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{39 b^{3/4} d^4 \sqrt {a+b x}}+\frac {16 \sqrt {a+b x} (c+d x)^{3/4} (b c-a d)^2}{39 d^3}-\frac {40 (a+b x)^{3/2} (c+d x)^{3/4} (b c-a d)}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d} \]
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Rule 52
Rule 65
Rule 227
Rule 230
Rule 313
Rule 435
Rule 1213
Rule 1214
Rubi steps \begin{align*} \text {integral}& = \frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}-\frac {(10 (b c-a d)) \int \frac {(a+b x)^{3/2}}{\sqrt [4]{c+d x}} \, dx}{13 d} \\ & = -\frac {40 (b c-a d) (a+b x)^{3/2} (c+d x)^{3/4}}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}+\frac {\left (20 (b c-a d)^2\right ) \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx}{39 d^2} \\ & = \frac {16 (b c-a d)^2 \sqrt {a+b x} (c+d x)^{3/4}}{39 d^3}-\frac {40 (b c-a d) (a+b x)^{3/2} (c+d x)^{3/4}}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}-\frac {\left (8 (b c-a d)^3\right ) \int \frac {1}{\sqrt {a+b x} \sqrt [4]{c+d x}} \, dx}{39 d^3} \\ & = \frac {16 (b c-a d)^2 \sqrt {a+b x} (c+d x)^{3/4}}{39 d^3}-\frac {40 (b c-a d) (a+b x)^{3/2} (c+d x)^{3/4}}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}-\frac {\left (32 (b c-a d)^3\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {a-\frac {b c}{d}+\frac {b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{39 d^4} \\ & = \frac {16 (b c-a d)^2 \sqrt {a+b x} (c+d x)^{3/4}}{39 d^3}-\frac {40 (b c-a d) (a+b x)^{3/2} (c+d x)^{3/4}}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}+\frac {\left (32 (b c-a d)^{7/2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a-\frac {b c}{d}+\frac {b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{39 \sqrt {b} d^4}-\frac {\left (32 (b c-a d)^{7/2}\right ) \text {Subst}\left (\int \frac {1+\frac {\sqrt {b} x^2}{\sqrt {b c-a d}}}{\sqrt {a-\frac {b c}{d}+\frac {b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{39 \sqrt {b} d^4} \\ & = \frac {16 (b c-a d)^2 \sqrt {a+b x} (c+d x)^{3/4}}{39 d^3}-\frac {40 (b c-a d) (a+b x)^{3/2} (c+d x)^{3/4}}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}+\frac {\left (32 (b c-a d)^{7/2} \sqrt {\frac {d (a+b x)}{-b c+a d}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+\frac {b x^4}{\left (a-\frac {b c}{d}\right ) d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{39 \sqrt {b} d^4 \sqrt {a+b x}}-\frac {\left (32 (b c-a d)^{7/2} \sqrt {\frac {d (a+b x)}{-b c+a d}}\right ) \text {Subst}\left (\int \frac {1+\frac {\sqrt {b} x^2}{\sqrt {b c-a d}}}{\sqrt {1+\frac {b x^4}{\left (a-\frac {b c}{d}\right ) d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{39 \sqrt {b} d^4 \sqrt {a+b x}} \\ & = \frac {16 (b c-a d)^2 \sqrt {a+b x} (c+d x)^{3/4}}{39 d^3}-\frac {40 (b c-a d) (a+b x)^{3/2} (c+d x)^{3/4}}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}+\frac {32 (b c-a d)^{15/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{39 b^{3/4} d^4 \sqrt {a+b x}}-\frac {\left (32 (b c-a d)^{7/2} \sqrt {\frac {d (a+b x)}{-b c+a d}}\right ) \text {Subst}\left (\int \frac {\sqrt {1+\frac {\sqrt {b} x^2}{\sqrt {b c-a d}}}}{\sqrt {1-\frac {\sqrt {b} x^2}{\sqrt {b c-a d}}}} \, dx,x,\sqrt [4]{c+d x}\right )}{39 \sqrt {b} d^4 \sqrt {a+b x}} \\ & = \frac {16 (b c-a d)^2 \sqrt {a+b x} (c+d x)^{3/4}}{39 d^3}-\frac {40 (b c-a d) (a+b x)^{3/2} (c+d x)^{3/4}}{117 d^2}+\frac {4 (a+b x)^{5/2} (c+d x)^{3/4}}{13 d}-\frac {32 (b c-a d)^{15/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} E\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{39 b^{3/4} d^4 \sqrt {a+b x}}+\frac {32 (b c-a d)^{15/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{39 b^{3/4} d^4 \sqrt {a+b x}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.03 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.28 \[ \int \frac {(a+b x)^{5/2}}{\sqrt [4]{c+d x}} \, dx=\frac {2 (a+b x)^{7/2} \sqrt [4]{\frac {b (c+d x)}{b c-a d}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {7}{2},\frac {9}{2},\frac {d (a+b x)}{-b c+a d}\right )}{7 b \sqrt [4]{c+d x}} \]
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\[\int \frac {\left (b x +a \right )^{\frac {5}{2}}}{\left (d x +c \right )^{\frac {1}{4}}}d x\]
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\[ \int \frac {(a+b x)^{5/2}}{\sqrt [4]{c+d x}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \]
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\[ \int \frac {(a+b x)^{5/2}}{\sqrt [4]{c+d x}} \, dx=\int \frac {\left (a + b x\right )^{\frac {5}{2}}}{\sqrt [4]{c + d x}}\, dx \]
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\[ \int \frac {(a+b x)^{5/2}}{\sqrt [4]{c+d x}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \]
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\[ \int \frac {(a+b x)^{5/2}}{\sqrt [4]{c+d x}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \]
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Timed out. \[ \int \frac {(a+b x)^{5/2}}{\sqrt [4]{c+d x}} \, dx=\int \frac {{\left (a+b\,x\right )}^{5/2}}{{\left (c+d\,x\right )}^{1/4}} \,d x \]
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